Difference between revisions of "Self join Quiz"

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SELF JOIN quiz
 
SELF JOIN quiz
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<div class='schema'></div>
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<div class = 'ref_section'>
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<table class = 'db_ref'>
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<tr><th>'''stops'''</th><th>'''route'''</th></tr>
 +
<tr><td>id</td><td>num</td></tr>
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<tr><td>name</td><td>company</td></tr>
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<tr><td></td><td>pos</td></tr>
 +
<tr><td></td><td>stop</td></tr>
 +
<tr><td></td><td></td></tr>
 +
</table>
 +
</div>
 +
 
<quiz shuffle=none display=simple>
 
<quiz shuffle=none display=simple>
 
{Select the code that would show it is possible to get from Craiglockhart to Haymarket
 
{Select the code that would show it is possible to get from Craiglockhart to Haymarket
 
|type="()"}
 
|type="()"}
- SELECT DISTINCT a.name, b.name from stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+
- <syntaxhighlight lang='sql'>SELECT DISTINCT a.name, b.name from stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'</syntaxhighlight>
- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+
- <syntaxhighlight lang='sql'>SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'</syntaxhighlight>
+ SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+
+ <syntaxhighlight lang='sql'>SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'</syntaxhighlight>
- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Sighthill'
+
- <syntaxhighlight lang='sql'>SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Sighthill'</syntaxhighlight>
- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where y.name='Craiglockhart' AND z.name ='Haymarket'
+
- <syntaxhighlight lang='sql'>SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where y.name='Craiglockhart' AND z.name ='Haymarket'</syntaxhighlight>
  
 
{Select the code that shows the stops that are on route.num '2A' which can be reached with one bus from Haymarket?
 
{Select the code that shows the stops that are on route.num '2A' which can be reached with one bus from Haymarket?
 
|type="()"}
 
|type="()"}
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
+
- <syntaxhighlight lang='sql'>SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R1.num='2A'</syntaxhighlight>
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
+
- <syntaxhighlight lang='sql'>SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'</syntaxhighlight>
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id
+
- <syntaxhighlight lang='sql'>SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id</syntaxhighlight>
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'
+
- <syntaxhighlight lang='sql'>SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'</syntaxhighlight>
+ SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
+
+ <syntaxhighlight lang='sql'>SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'</syntaxhighlight>
  
  
 
{Select the code that shows the services available from Tollcross?
 
{Select the code that shows the services available from Tollcross?
 
|type="()"}
 
|type="()"}
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)
+
- <syntaxhighlight lang='sql'>SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)</syntaxhighlight>
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'
+
- <syntaxhighlight lang='sql'>SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'</syntaxhighlight>
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
+
- <syntaxhighlight lang='sql'>SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'</syntaxhighlight>
+ SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
+
+ <syntaxhighlight lang='sql'>SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'</syntaxhighlight>
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'
+
- <syntaxhighlight lang='sql'> SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'</syntaxhighlight>
 
   
 
   
 
</quiz>
 
</quiz>
  
 
[[Category:Quizzes]]
 
[[Category:Quizzes]]

Revision as of 11:02, 12 July 2013

SELF JOIN quiz

stopsroute
idnum
namecompany
pos
stop

<quiz shuffle=none display=simple> {Select the code that would show it is possible to get from Craiglockhart to Haymarket |type="()"}

-
SELECT DISTINCT a.name, b.name FROM stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id WHERE a.name='Craiglockhart' AND b.name ='Haymarket'
-
SELECT DISTINCT a.name, b.name FROM stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id WHERE a.name='Craiglockhart' AND b.name ='Haymarket'
+
SELECT DISTINCT a.name, b.name FROM stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id WHERE a.name='Craiglockhart' AND b.name ='Haymarket'
-
SELECT DISTINCT a.name, b.name FROM stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id WHERE a.name='Craiglockhart' AND b.name ='Sighthill'
-
SELECT DISTINCT a.name, b.name FROM stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id WHERE y.name='Craiglockhart' AND z.name ='Haymarket'

{Select the code that shows the stops that are on route.num '2A' which can be reached with one bus from Haymarket? |type="()"}

-
SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R1.num='2A'
-
SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
-
SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id
-
SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'
+
SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'


{Select the code that shows the services available from Tollcross? |type="()"}

-
SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)
-
SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'
-
SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
+
SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
-
 SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'

</quiz>