Self join Quiz - Revision history

Yarre: 2.1 and 2.5 variants was identical

2013-04-14T06:58:47Z

2.1 and 2.5 variants was identical

Trust words at 10:02, 30 September 2012

2012-09-30T10:02:35Z

Connor at 14:44, 7 August 2012

2012-08-07T14:44:59Z

Connor at 11:03, 23 July 2012

2012-07-23T11:03:37Z

Connor at 10:50, 23 July 2012

2012-07-23T10:50:06Z

Connor: Created page with "SELF JOIN quiz {Which of following would show it is possible to get from Craiglockhart to Haymarket |type="()"} - select distinct a.name, b...."

2012-07-19T09:49:17Z

Created page with "SELF JOIN quiz <quiz shuffle=none display=simple> {Which of following would show it is possible to get from Craiglockhart to Haymarket |type="()"} - select distinct a.name, b...."

New page

SELF JOIN quiz
<quiz shuffle=none display=simple>
{Which of following would show it is possible to get from Craiglockhart to Haymarket
|type="()"}
- select distinct a.name, b.name from stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
- select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+ select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
- select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Sighthill'
- select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where y.name='Craiglockhart' AND z.name ='Haymarket'

{Which of the following shows the stops that are on route.num '2A' which can be reached with one bus from Haymarket?
|type="()"}
- S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id
- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'
+ SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'

{Which of the following shows the services available from Tollcross?
|type="()"}
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
+ SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'

</quiz>

[[Category:Quizzes]]

@@ Line 3: / Line 3: @@
 {Select the code that would show it is possible to get from Craiglockhart to Haymarket
 |type="()"}
--A. select distinct a.name, b.name from stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+- SELECT DISTINCT a.name, b.name from stops a JOIN route z IN a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b IN y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
--B. select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
+- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
-+C. select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
++ SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Haymarket'
--D. select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Sighthill'
+- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where a.name='Craiglockhart' AND b.name ='Sighthill'
--E. select distinct a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where y.name='Craiglockhart' AND z.name ='Haymarket'
+- SELECT DISTINCT a.name, b.name from stops a JOIN route z ON a.id=z.stop JOIN route y ON y.num = z.num JOIN stops b ON y.stop=b.id where y.name='Craiglockhart' AND z.name ='Haymarket'
 {Select the code that shows the stops that are on route.num '2A' which can be reached with one bus from Haymarket?
 |type="()"}
--A. S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
+- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
--B. SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
+- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Craiglockhart' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
--C. SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id
+- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id
--D. SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'
+- SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2'
-+E. SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
++ SELECT S2.id, S2.name, R2.company, R2.num FROM stops S1, stops S2, route R1, route R2 WHERE S1.name='Haymarket' AND S1.id=R1.stop AND R1.company=R2.company AND R1.num=R2.num AND R2.stop=S2.id AND R2.num='2A'
 {Select the code that shows the services available from Tollcross?
 |type="()"}
--A. SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)
+- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id)
--B. SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'
+- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Sighthill'
--C. SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
+- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b IN (a.company=b.company AND a.num=b.num) JOIN stops stopa IN (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
-+D. SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
++ SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopa.name='Tollcross'
--E. SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'
+- SELECT a.company, a.num, stopa.name, stopb.name FROM route a JOIN route b ON (a.company=b.company AND a.num=b.num) JOIN stops stopa ON (a.stop=stopa.id) JOIN stops stopb ON (b.stop=stopb.id) WHERE stopz.name='Tollcross'
 </quiz>
 [[Category:Quizzes]]

@@ Line 1: / Line 1: @@
 SELF JOIN quiz
 <quiz shuffle=none display=simple>
 {Select the code that would show it is possible to get from Craiglockhart to Haymarket